Lars has $90 to buy tickets to the zoo for some of his family. He will buy an equal number of child and adult tickets.
Ticket Cost ($)
Child 7.00
Adult 12.00
The inequality 7n+12n≤90 can be used to find the number of each type of ticket he can buy. What is the greatest number of each type of ticket that Lars can buy?
He can buy -BLANK- child tickets and -BLANK- adult tickets.
He can buy 10 child tickets and 8 adult tickets.
To find the greatest number of child and adult tickets that Lars can buy, we need to solve the inequality 7n + 12n ≤ 90, where n represents the number of tickets.
First, let's combine the like terms:
7n + 12n ≤ 90
19n ≤ 90
Now, we can solve for n by dividing both sides of the inequality by 19:
n ≤ 90/19
n ≤ 4.7368
Since the number of tickets cannot be a decimal or fraction, we need to round down to the nearest whole number. Thus, Lars can buy a maximum of 4 child tickets and 4 adult tickets.
To find the greatest number of each type of ticket that Lars can buy, we need to solve the inequality 7n + 12n ≤ 90, where n represents the number of tickets.
Combining like terms, we have 19n ≤ 90.
To isolate n, we can divide both sides of the inequality by 19:
(19n)/19 ≤ 90/19
Simplifying, we get n ≤ 4.74.
Since the number of tickets must be a whole number, Lars can buy a maximum of 4 child tickets and 4 adult tickets.
Therefore, he can buy 4 child tickets and 4 adult tickets.