What is the mass of solute in 500cm3 of 0.005moldm−3 H2SO4? ( H = 1, S = 32.0, O=16.0)
A. 0.490g
B. 0.049g
C. 0.245g
D. 0.0245g
B. 0.049g
To find the mass of solute in 500cm3 of 0.005moldm−3 H2SO4, we can use the formula:
Mass of solute = concentration × volume
First, calculate the molar mass of H2SO4:
2H = 2 × 1.00 g/mol = 2.00 g/mol
1S = 1 × 32.0 g/mol = 32.0 g/mol
4O = 4 × 16.0 g/mol = 64.0 g/mol
Total molar mass of H2SO4 = 2.00 + 32.0 + 64.0 = 98.0 g/mol
Now we can substitute the values into the formula:
Mass of solute = 0.005 mol/dm^3 × 500 cm^3 × (1 dm^3/1000 cm^3) × 98.0 g/mol
Simplifying the units and calculating:
Mass of solute = 0.005 × 500 × (1/1000) × 98.0 g
Mass of solute = 0.0245 g
Therefore, the correct answer is D. 0.0245g.