In a certain Algebra 2 class of 22 students, 5 of them play basketball and 11 of them play baseball. There are 3 students who play both sports. What is the probability that a student chosen randomly from the class plays basketball or baseball?
I believe 13/22 would be your answer. Let me know if I'm incorrect.
To find the probability that a student chosen randomly from the class plays basketball or baseball, we need to find the total number of students who play basketball or baseball.
We are given that there are 5 students who play basketball, 11 students who play baseball, and 3 students who play both sports.
To find the total number of students who play basketball or baseball, we can add the number of basketball players and the number of baseball players. However, we need to subtract the number of students who play both sports once to avoid counting them twice.
So, total number of students who play basketball or baseball = (number of basketball players) + (number of baseball players) - (number of students who play both sports)
= 5 + 11 - 3
= 13
Now, we can calculate the probability that a student chosen randomly from the class plays basketball or baseball by dividing the total number of students who play basketball or baseball by the total number of students in the class.
Probability = (number of students who play basketball or baseball) / (total number of students in the class)
= 13 / 22
Therefore, the probability that a student chosen randomly from the class plays basketball or baseball is 13/22, which can also be simplified as approximately 0.59 or 59%.
The probability that a student chosen randomly from the class plays basketball or baseball is 18/22, or approximately 0.818.
my bad
16 play only basketball
5 play only baseball
19/29 + 5/29 = 24/.29