A scientist heats 30 grams of calcium carbonate CaVO3 in the chemical reaction shown. What is the total mass of the products?
The total mass of the products is 44 grams.
To determine the total mass of the products in a chemical reaction, we need to first balance the equation.
The balanced equation for the reaction of calcium carbonate (CaCO3) is:
CaCO3 -> CaO + CO2
The molar mass of CaCO3 is 100.09 g/mol, and since we have 30 grams of CaCO3, we can calculate the number of moles using the formula:
moles = mass / molar mass
moles = 30 g / 100.09 g/mol ≈ 0.2999 mol
From the balanced equation, we can see that one mole of CaCO3 produces one mole of CaO and one mole of CO2. Therefore, the total moles of products will also be 0.2999 mol.
To find the total mass of the products, we multiply the total moles of products by their respective molar masses and sum them up:
Total mass of products = (moles of CaO × molar mass of CaO) + (moles of CO2 × molar mass of CO2)
The molar mass of CaO is 56.08 g/mol, and the molar mass of CO2 is 44.01 g/mol.
Total mass of products = (0.2999 mol × 56.08 g/mol) + (0.2999 mol × 44.01 g/mol) ≈ 16.82 g + 13.20 g ≈ 30.02 g
Therefore, the total mass of the products in this reaction is approximately 30.02 grams.
To determine the total mass of the products, we first need to know the chemical equation for the reaction. However, you have only provided the formula for calcium carbonate, which is CaCO3, not CaVO3.
If we assume that the reactant is indeed CaCO3 and it undergoes a simple heating reaction, the balanced chemical equation would be:
CaCO3(s) → CaO(s) + CO2(g)
From this equation, we can see that calcium carbonate decomposes into calcium oxide (CaO) and carbon dioxide (CO2).
To calculate the mass of each product, we need to know the molar masses of calcium carbonate, calcium oxide, and carbon dioxide.
The molar mass of CaCO3 can be calculated by adding up the atomic masses of the constituent elements Ca, C, and O:
Molar mass of CaCO3 = (40.08 g/mol) + (12.01 g/mol) + (3 * 16.00 g/mol) = 100.09 g/mol
The molar mass of CaO is calculated similarly:
Molar mass of CaO = 40.08 g/mol + 16.00 g/mol = 56.08 g/mol
The molar mass of CO2 is:
Molar mass of CO2 = 12.01 g/mol + (2 * 16.00 g/mol) = 44.01 g/mol
Now, let's calculate the amount of each product formed based on the given mass of calcium carbonate (30 grams) and the molar ratios from the balanced equation:
For CaCO3:
Moles of CaCO3 = mass / molar mass = 30 g / 100.09 g/mol = 0.2996 mol
According to the balanced equation, the molar ratio between CaCO3 and CaO is 1:1. Therefore, the moles of CaO formed would also be 0.2996 mol.
For CO2:
Moles of CO2 = moles of CaCO3 = 0.2996 mol
Now, let's convert the moles of each product back into masses:
Mass of CaO = moles of CaO * molar mass of CaO = 0.2996 mol * 56.08 g/mol = 16.81 g
Mass of CO2= moles of CO2 * molar mass of CO2 = 0.2996 mol * 44.01 g/mol = 13.20 g
Therefore, the total mass of the products (CaO + CO2) would be:
16.81 g + 13.20 g = 30.01 g
So, the total mass of the products would be approximately 30.01 grams.