a current of 4.5a is passed through a solution of gold salt for 1 hour 45 minutes.calculate the number of moles of gold deposited according to michael faraday's law
The number of moles of gold deposited can be calculated using Faraday's Law, which states that the amount of substance produced is equal to the charge (in coulombs) divided by the Faraday constant (96,485 C/mol).
In this case, the charge is 4.5 A x 1.45 hours x 3600 seconds/hour = 16,020 C.
Therefore, the number of moles of gold deposited is 16,020 C / 96,485 C/mol = 0.166 moles.
To calculate the number of moles of gold deposited using Michael Faraday's law, we need to know the charge (Q) passed through the solution and the Faraday constant (F). The charge can be calculated using the formula:
Q = I * t
Where:
- I is the current in amperes
- t is the time in seconds
Given:
Current (I) = 4.5 A
Time (t) = 1 hour 45 minutes = (1 * 60 * 60) + (45 * 60) seconds
Let's calculate the charge:
t = (1 * 60 * 60) + (45 * 60)
t = 3600 + 2700
t = 6300 seconds
Q = I * t
Q = 4.5 * 6300
Q = 28350 Coulombs
Now, we need the Faraday constant, which represents the charge per mole of electrons. The value of the Faraday constant is approximately 96,485 Coulombs/mol (to three significant figures).
To calculate the number of moles of gold deposited, divide the charge (Q) by the Faraday constant (F):
Number of moles (n) = Q / F
n = 28350 / 96485
n ≈ 0.294 moles
Therefore, approximately 0.294 moles of gold are deposited according to Michael Faraday's law.