Is the volume of a cone with a base radius of 4 in and height of 3 in
equal to 50.24 in^3?
Yes, the volume of a cone with a base radius of 4 in and height of 3 in is equal to 50.24 in^3.
To calculate the volume of a cone, you can use the formula:
V = (1/3)πr^2h
where V is the volume, π is a mathematical constant approximately equal to 3.14159, r is the base radius of the cone, and h is the height of the cone.
In this case, the base radius (r) is given as 4 inches and the height (h) is given as 3 inches.
Plugging these values into the formula, we have:
V = (1/3)π(4^2)(3)
= (1/3)π(16)(3)
= (1/3)π(48)
≈ (1/3)(3.14159)(48)
≈ (0.33333)(150.79656)
≈ 50.26548
Therefore, the volume of the cone with a base radius of 4 inches and a height of 3 inches is approximately 50.26548 cubic inches.
To find the volume of a cone, we can use the formula V = (1/3)πr^2h, where V is the volume, r is the base radius, and h is the height.
Given that the base radius (r) is 4 in and the height (h) is 3 in, we can plug these values into the formula to calculate the volume.
V = (1/3)π(4^2)(3)
= (1/3)π(16)(3)
= (1/3)π(48)
= 16π
≈ 50.27 cubic inches (rounded to two decimal places)
Therefore, the volume of the cone with a base radius of 4 in and a height of 3 in is approximately 50.27 cubic inches.