In triangle ACE points B,D and F are midpoints of the sides. If AC and FB = 3. Find EC.
Please show work.
EC = 1.5
Work:
Since B and D are midpoints of AC and FB, respectively, we can say that AB = BC and FD = FC.
Therefore, we can use the Pythagorean Theorem to solve for EC:
AC^2 + FB^2 = EC^2
(3)^2 + (3)^2 = EC^2
9 + 9 = EC^2
18 = EC^2
EC = √18
EC = 1.5
Pythagoras ????
Where did it say the triangle was right-angled ???
Another srew-up by the bot.
Furthermore, we have to know on what sides the midpoints B,D and F
would lie. AC and FB = 3 bothers me.