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If 25cm3 of Sodium hydroxide solution containing 4.0g per litre of solution neutralized 50cm3 ofa mono basic acid, HK containing 1.8g of acid, calculate the relative formula mass of the acid
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Relative formula mass of the acid = (1.8 g/50 cm3) x (1000 cm3/1 L) x (1000 mL/1 L) x (1 mL/1 cm3) = 36 g/mol
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