Questions LLC
Login
or
Sign Up
Ask a New Question
Science
Chemistry
If 25cm3 of Sodium hydroxide solution containing 4.0g per litre of a solution neutralized 50cm3 ofa mono basic acid, HK containing 1.8g of acid, calculate the relative formula mass of the acid.
1 answer
Relative formula mass of the acid = (1.8 g/50 cm3) x (1000 cm3/1 L) = 36 g/L
You can
ask a new question
or
answer this question
.
Related Questions
25cm3 of a solution of 0.1mol dm-3 NaoH reacts with 50cm3 of a solution of hydrochloric acid.What is the molarity of the acid
When 2.25 g of sodium hydroxide (NaOH) was dissolved in 150.00 g of water a value of 11.00oC was obtained for ΔT.
1. Calculate
A solution of trioxonitrate (V) acid contained 0.67g in 100cm3. 31.0cm3 of this solution
neutralized 25cm3 of a sodium
A is a solution of trioxonitrate (v)acid, HNO3 of unknown concentration.B is standard solution of sodium hydroxide containing
A is a solution of trioxonitrate(v) acid, HNO3, of unknown concentration. B is standard solution of sodium hydroxide containing
Starting with 50cm³ of 2.8M sodium hydroxide, describe how a sample of pure sodium sulphate crystals can be prepared
Assuming titration was carried out between sodium hydrogen tetraoxosulphate (vi)(NaHSo) of concentration 12.0gdm-² as solution
The approximate concentration of a hydrochloric acid solution is 0.5M. The exact concentration of this solution is to be
A is a solution of tetraoxosulphate (vi) acid, B is a solution containing 1.4g of potassium hydroxide per 250cm3.
using the table
25cm3 Of 3g Of Hydrated Sodium Trioxocarbonate(iv) Solution (NaCO3XH2O)Per 250cm3 Was Neutralized By 13.20cm3 Of 0.16m