Write the following expression as a single complex number.
(1 – 3i)(2 + 4i)
Once again, MrNobody has flubbed the answer.
(1 – 3i)(2 + 4i)
= 1(2+4i) - 3i(2+4i)
= 2 + 4i - 6i - 12i^2
= 2+12 -2i
= 14-2i
(1 – 3i)(2 + 4i)
(1 – 3i)(2 + 4i)
= 1(2+4i) - 3i(2+4i)
= 2 + 4i - 6i - 12i^2
= 2+12 -2i
= 14-2i