Find the diagonal of the box, AD, using the Pythagorean Theorem twice - 1. To find BD, and 2. To find AD.
AB = 12 in
BC = 18 in
CD = 4 in
Show all steps for finding the diagonal of the box above using the formula instead of the Pythagorean Theorem twice.
Formula: c^2 = a^2 + b^2
Step 1: Find BD
c^2 = 12^2 + 18^2
c^2 = 144 + 324
c^2 = 468
c = 21.6 in
Step 2: Find AD
c^2 = 21.6^2 + 4^2
c^2 = 468.16 + 16
c^2 = 484.16
c = 22 in
Therefore, the diagonal of the box, AD, is 22 in.
Assuming that the sides of the box are 12, 18, and 4
(no idea where A, B, etc are located)
diagonal^2 = 12^2 + 18^2 + 4^2
= 144 + 324 + 16
= 484
diagonal = √484 = 22
final answer!