9x² - 16y² - 36x - 96y - 252 = 0
9(x^ - 2)^2 - 16(y+3)^2 = 144 (x-2)^2/16 - (y+3)^2/9 = 1 so we have, knowing that the axis of symmetry is the line y = -3 center: (2,-3) vertices (a=4): (2±4,-3) foci (c=5): (2±5,-3) ftransverse axis = 2a = 8 conjugate axis = 2b = 6 asymptotes (±b/a) : y+3 = ±3/4 (x-2)
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