Calculate the percentage of carbon in ethanedioic acid Crystal
C2H2O4.2H2O.
mm = molar mass
am = atomic mass
%C = (2*am C)*100/mm C2H2O4.2H2O
%H = (6*am H)*100/mm C2H2O4.2H2O
%O = (6*am O)*100/mm C2H2O4.2H2O
Check it to see that the total is 100%.
To calculate the percentage of carbon in ethanedioic acid crystal (C2H2O4·2H2O), you need to determine the molar mass of carbon and the molar mass of the compound.
1. Calculate the molar mass of carbon (C):
The atomic mass of carbon is 12.01 g/mol.
2. Calculate the molar mass of the compound (C2H2O4·2H2O):
- Two carbon atoms: (2 * 12.01 g/mol) = 24.02 g/mol
- Two hydrogen atoms: (2 * 1.01 g/mol) = 2.02 g/mol
- Four oxygen atoms in the acid: (4 * 16.00 g/mol) = 64.00 g/mol
- Two water molecules: (2 * [(2 * 1.01 g/mol) + (1 * 16.00 g/mol)]) = 72.08 g/mol
Total molar mass of the compound = (24.02 g/mol) + (2.02 g/mol) + (64.00 g/mol) + (72.08 g/mol) = 162.12 g/mol
3. Calculate the percentage of carbon in the compound:
Carbon's contribution to the total molar mass = (24.02 g/mol) / (162.12 g/mol)
4. Convert the fraction to a percentage:
Percentage of carbon = (24.02 g/mol) / (162.12 g/mol) * 100
Therefore, the percentage of carbon in ethanedioic acid crystal is approximately 14.80%.