Solve the given equation.
tan^4(π) β 34 tan^2(π) + 225 = 0
c'mon, this is just a quadratic equation in tan^2ΞΈ
(tan^2ΞΈ-9)(tan^2ΞΈ-25) = 0
tanΞΈ = Β±3
tanΞΈ = Β±5
so it looks like each case has a solution in each quadrant.
tan^4(π) β 34 tan^2(π) + 225 = 0
(tan^2ΞΈ-9)(tan^2ΞΈ-25) = 0
tanΞΈ = Β±3
tanΞΈ = Β±5
so it looks like each case has a solution in each quadrant.