The triangle shown has vertices A(−12,−10), B(15,−10), and C(10,5). If the triangle is dilated and the new image of point C lies at (8,4), where is the resulting image of point B after the dilation?
(8/4) = (10,5) * 4/5
so multiply all coordinates by 4/5
(x,y) ---> (4x/5 , 4y/5)
C(10,5)-----> C' (8,4)
A(-12,-10) ----> A' (-48/5 , -8)
B(15, -10) -----> B' (12, -8)