Question

Log10 base 5(3/5)+3 log(15/2) base 5- log(81/8) base 5

Answer 1

so, with all logs base 5, we have (not sure what to do with the (3/5)

log10 + 3log(15/2) - log(81/8)
= log2 + log5 + 3log5 + 3log3 - 3log2 - 4log3 + 3log2
= 4log2 - 2log3 + 4log5
= log ₅144 + 4

maybe if you fix your typo you can sraighten it out