The time it takes the population of a microrganism to reduce by half is 0.000027503 of a year. what number is the best estimation of this Quantity?
Found the answer! This question isn't asking us to work the problem, sheesh! It's asking us to estimate THIS quantity, therefore the answer is 0.00003
I how this helps others.
To find the best estimation of the quantity, we can convert 0.000027503 of a year to a more convenient unit such as seconds.
1 year = 365 days = 24 hours/day = 60 minutes/hour = 60 seconds/minute
Therefore, 0.000027503 of a year can be calculated as:
0.000027503 year * 365 days/year * 24 hours/day * 60 minutes/hour * 60 seconds/minute ≈ 0.87 seconds
So, the best estimation of the quantity is approximately 0.87 seconds.
To find the best estimation of the quantity, we need to determine the number that corresponds to reducing the population by half in 0.000027503 of a year. Since we know that reducing by half means dividing by 2, we can set up the following equation:
population at time t = initial population / (2^(t / 0.000027503))
To find the best estimation, we need to calculate t when the population is reduced by half. Rearranging the equation:
0.5 = initial population / (2^(t / 0.000027503))
Now, isolate t:
t / 0.000027503 = log base 2 (initial population / 0.5)
t = (0.000027503) * log base 2 (initial population / 0.5)
Since we don't have the initial population value, it is not possible to find the exact best estimation. However, if you provide the initial population value, I can calculate the best estimation for you.