Two workers are sliding a 300 kg crate across the floor. One worker pushes forward on the crate with a force of 380 N while the other pulls in the same direction with a force of 350 N using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate’s coefficient of kinetic friction on the floor?

Question

Two workers are sliding a 300 kg crate across the floor. One  worker pushes forward on the crate with a force of 380 N while  the other pulls in the same direction with a force of 350 N using  a rope connected to the crate. Both forces are horizontal, and  the crate slides with a constant speed. What is the crate’s coefficient of kinetic friction on the floor?

Anonymous · Accepted Answer

total forward force = 380 + 350 = 730 Newtons forward no acceleration so friction force is 730 backward 730 = mu m g = mu * 300 * 9.81 mu = 0.248