What volume of a 0.500 M sucrose ( C12H22O11 ) solution contains 60.8 g of sucrose?
first, find the molar mass of sucrose (342.30g/mol). then, find how many moles of sucrose you need to get to 60.8g. then, double that because youre starting with half a mole of sucrose per liter of solution.
so...
60.8/342.30 = 0.1776
0.1776*2 = 0.355
so 0.355 liters would contain 60.8g of sucrose
Just another way, but not a bettr way, to look at the same problem.
mols sucrose in 60.8 g = grams/molar mass = 60.8/342.3 = 0.178
mols = M x L = 0.178
0.178 = 0.500 x L
L = 0.178/0.500 = 0.0356 L = 35.6 mL
To find the volume of the sucrose solution, we can use the formula:
Volume (V) = Mass (m) / Concentration (C)
Given:
Mass of sucrose (m) = 60.8 g
Concentration of sucrose solution (C) = 0.500 M
Plugging in the values into the formula:
V = 60.8 g / 0.500 M
V = 121.6 mL
Therefore, the volume of the 0.500 M sucrose solution containing 60.8 g of sucrose is 121.6 mL.
To find the volume of the solution, we can use the equation:
Volume (V) = Mass (m) / Concentration (C)
In this case, the given mass of sucrose is 60.8 g, and the concentration of the sucrose solution is 0.500 M.
First, let's convert the mass of sucrose from grams to moles. To do this, we need to know the molar mass of sucrose (C12H22O11).
The molar mass of sucrose can be calculated by summing the atomic masses of carbon (C), hydrogen (H), and oxygen (O) in the molecule:
Molar mass of C12H22O11 = (12.01 g/mol * 12) + (1.01 g/mol * 22) + (16.00 g/mol * 11)
Molar mass of C12H22O11 = 144.12 g/mol + 22.22 g/mol + 176.00 g/mol
Molar mass of C12H22O11 ≈ 342.34 g/mol
Next, let's convert the given mass of sucrose to moles:
Moles of sucrose = Mass of sucrose / Molar mass of sucrose
Moles of sucrose = 60.8 g / 342.34 g/mol
Moles of sucrose ≈ 0.1778 mol
Now that we have the number of moles of sucrose, we can use the concentration of the solution to find the volume:
Volume of solution = Moles of solute / Concentration of solution
Volume of solution = 0.1778 mol / 0.500 M
Volume of solution = 0.3556 L or 355.6 mL
Therefore, the volume of the 0.500 M sucrose solution that contains 60.8 g of sucrose is approximately 0.3556 liters or 355.6 milliliters.