what is the force exerted by a catcher's glove on a 0.15kg baseball moving at 37m/s that is stopped in 0.02s?
To calculate the force exerted by a catcher's glove on a baseball, you can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the acceleration is determined by the change in velocity and the time it takes to stop the baseball.
First, you need to calculate the acceleration (a) using the equation:
a = (final velocity - initial velocity) / time
In this case, the initial velocity (u) is 37 m/s, the final velocity (v) is 0 m/s (since the baseball is stopped), and the time (t) is 0.02 s.
a = (0 - 37) m/s / 0.02 s
Next, plug in the values and calculate the acceleration:
a = -1850 m/s^2
Since the acceleration is negative, it indicates deceleration, as the baseball stops.
Now, you can calculate the force (F) using the equation:
F = m * a
Given that the mass (m) of the baseball is 0.15 kg and the acceleration (a) is -1850 m/s^2, you can substitute these values into the formula and calculate the force:
F = 0.15 kg * -1850 m/s^2
Finally, perform the calculation to determine the force:
F = -277.5 N
Therefore, the force exerted by the catcher's glove is approximately -277.5 newtons. The negative sign indicates that the force is in the opposite direction of the initial motion of the baseball.