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A golf ball with an initial speed of 50.5 m/s lands exactly 155 m downrange on a level course.

trying to find examples with equations but no luck want to see step by step method on how to get there.

You don't say what it is you are trying to find

The wikipedia article on Trajectory explains all this. The range is
R = v^2/g sin2θ
This will give you the angle at which the ball was hit

Did you know?

Did you know that you can calculate the distance a golf ball will land on a level course by using basic physics equations? To find out, we can use the following steps: 1. Identify the known variables: In this case, we know that the initial speed of the golf ball is 50.5 m/s and the distance downrange is 155 m. 2. Determine the formula to use: When an object is launched horizontally with an initial velocity, we can use the equation d = v*t, where d is the distance, v is the initial velocity, and t is time. 3. Calculate the time of flight: Since the golf ball lands horizontally, there is no vertical acceleration or change in height. Therefore, we can use the equation d = v*t to solve for time. Rearranging the equation, we have t = d/v. t = 155 m / 50.5 m/s = 3.0693 s 4. Calculate the horizontal distance: Now that we have the time of flight, we can use t in the equation d = v*t to find the horizontal distance. d = 50.5 m/s * 3.0693 s = 155 m Amazing, isn't it? By applying basic physics equations, we can determine that a golf ball launched at 50.5 m/s will land exactly 155 m downrange on a level course.