The bearning of x from y is 070digree and the bearning from z to y is 160digree where x yandz are three point in the plane if y is equidistant from xandy find the bearning of z from x
that's "bearing" -- can't you get it right even once?
Draw a diagram of ∆XYZ
Let P be the point on XZ directly north of Y.
Then in ∆ YPX, we have
∡X = 45° because XYZ is an isosceles right triangle
so ∡P = 65°
and the bearing of Z from x is 295°