Using ethanol’s density of 0.789 g/mL, calculate the molarity of ethanol in a beer marked as 5.6%
alcohol. (Hint: 5.6% means 5.6mL of ethanol for every 100mL of solution)
So I know the formula for Molarity is Number of Moles/ Liters of Solution, however I'm confused on how to apply it, or even if it is applied to solve this question. Any help is deeply appreciated.
Mary
If you have 5.6 mL ethanol in 100 mL solution, then you have 56 mLethanol in 1 L of solution.
How many grams is that? mass = volume x density = 56 x 0.789 = ? grams ethanol. How many moles is that? That's
mols = grams/molar mass. You have grams and you have molar mass. Solve for mols
Then M = mols/L solutiion and you have it.
Well, Mary, let's try to figure this out together! To start, let's find out how many mL of ethanol are present in 100 mL of beer marked as 5.6% alcohol.
We know that the beer is 5.6% alcohol, which means that there are 5.6 mL of ethanol in every 100 mL of solution.
Now, we need to convert this into moles of ethanol. To do that, we must first calculate the mass of ethanol in the 5.6 mL.
The density of ethanol is given as 0.789 g/mL, so we can find the mass of ethanol using the following formula:
mass = density x volume
mass = 0.789 g/mL x 5.6 mL
Now, we can calculate the number of moles of ethanol present in the 5.6 mL using its molar mass (which is 46.07 g/mol):
moles = mass / molar mass
With the moles of ethanol in 5.6 mL known, we can now calculate the molarity. But first, we need to convert 5.6 mL to liters:
volume in liters = 5.6 mL / 1000 mL/L
Finally, we can apply the molarity formula:
Molarity = moles / volume in liters
Now you just have to plug in the values we obtained earlier, and you'll have your answer, Mary! I hope this helps, but if you need any more assistance, feel free to ask.
To calculate the molarity of ethanol in a beer marked as 5.6% alcohol, you will need to convert the given percentage into moles of ethanol.
First, let's calculate the amount of ethanol in one liter (1000 mL) of the beer:
5.6% alcohol means 5.6 mL ethanol for every 100 mL of solution.
So in one liter (1000 mL) of the solution, there would be (5.6 mL / 100 mL) * 1000 mL = 56 mL of ethanol.
Next, we need to convert the volume of ethanol into grams using the density of ethanol, which is 0.789 g/mL.
56 mL * 0.789 g/mL = 44.184 g of ethanol in one liter of the beer.
Now, we will convert grams of ethanol into moles using the molar mass of ethanol, which is 46.07 g/mol.
44.184 g / 46.07 g/mol = 0.958 moles of ethanol.
Finally, we can calculate the molarity of ethanol by dividing the moles of ethanol by the liters of solution:
Molarity = 0.958 moles / 1 liter = 0.958 M.
Therefore, the molarity of ethanol in the beer marked as 5.6% alcohol is 0.958 M.
To solve this question, you will need to convert the given percentage of ethanol to grams, and then calculate the molarity.
First, convert the percentage of ethanol (5.6%) to grams of ethanol per mL of solution:
5.6% means 5.6 grams of ethanol for every 100 mL of solution.
Converting this to grams per mL:
5.6 grams / 100 mL = 0.056 grams/mL
Now, we know the density of ethanol is 0.789 g/mL. By dividing the grams of ethanol per mL by the density, we can determine the volume of ethanol per mL:
0.056 grams/mL / 0.789 g/mL = 0.071 mL/mL
The resulting value of 0.071 mL/mL represents the volume fraction of ethanol in the solution.
To calculate the molarity, we need the number of moles of ethanol. We can find this by multiplying the volume fraction by the volume of the solution.
Let's assume we have a 100 mL solution (as given in the hint).
Number of moles of ethanol = volume fraction x volume of solution
= 0.071 mL/mL x 100 mL
= 7.1 mL
Now, we need to convert the moles of ethanol to liters:
7.1 mL x (1 L / 1000 mL) = 0.0071 L
Finally, we can calculate the molarity using the formula:
Molarity = Number of Moles / Liters of Solution
= 7.1 mol / 0.0071 L
= 1000 M
Therefore, the molarity of ethanol in the given beer is 1000 M.