The first three terms of an arithmetic progression X,(3x+1)and(7x-4). Find: (a)the value of x
(b) 10th term
since there is a common difference,
3x+1 = (x + 7x-4)/2
solve for x.
now you know that d = 2x+1 and
a10 = x+9d = 19x+9
(b) 10th term
3x+1 = (x + 7x-4)/2
solve for x.
now you know that d = 2x+1 and
a10 = x+9d = 19x+9