If 2 log x base 10 + 3 log 5 base 10 = 2. Find x
assuming base 10,
2logx + 3log5 = 2
log x^2 + log 5^3 = 2
log 125x^2 = 2
125x^2 = 100
x^2 = 100/125
x = 2/√5
2logx + 3log5 = 2
log x^2 + log 5^3 = 2
log 125x^2 = 2
125x^2 = 100
x^2 = 100/125
x = 2/√5