First 5 terms of the sequence whose general term is an=(n-3)n
yes
an=(n-3)n
simply replace n with 1, 2, 3, 4, 5
n1 = (1-3)(1) = -2
n2 = (2-3)(2) = -2
n3 = (3-3)(3) = 0
n4 = ....
n5 = ....
Just replace n by numbers.
a1 = ( 1 - 3 ) ∙ 1 = ( - 2 ) ∙ 1 = - 2
a2 = ( 2 - 3 ) ∙ 2 = ( - 1 ) ∙ 2 = - 2
a3 = ( 3 - 3 ) ∙ 3 = 0 ∙ 3 = 0
a4 = ( 4 - 3 ) ∙ 4 = 1 ∙ 4 = 4
a5 = ( 5 - 3 ) ∙ 5 = 2 ∙ 5 = 10
To find the first 5 terms of the sequence with the general term an = (n - 3)n, we can substitute different values of n into the formula to get the corresponding terms.
Let's plug in n = 1, 2, 3, 4, and 5 to find the first 5 terms:
For n = 1:
a1 = (1 - 3) * 1 = -2 * 1 = -2
For n = 2:
a2 = (2 - 3) * 2 = -1 * 2 = -2
For n = 3:
a3 = (3 - 3) * 3 = 0 * 3 = 0
For n = 4:
a4 = (4 - 3) * 4 = 1 * 4 = 4
For n = 5:
a5 = (5 - 3) * 5 = 2 * 5 = 10
Therefore, the first 5 terms of the sequence are -2, -2, 0, 4, and 10.