Potassium hydroxide was reacted with dilute sulphuric acid write the chemical equation for this reaction
b, Calculate the minimum volume of 0.1moldm-3 sulphuric acid that is reacted to completely react with 25.0cm3 of 0.4 moldm-3 potassium hydroxide
2KOH + H2SO4 ==> K2SO4 + 2H2O
millimols KOH = mL x M = 25 mL x 0.4 M = 10.0
It will take 10.0/2 = 5.0 millimoles H2SO4 to react completely.
M = millimoles/mL or mL = millimoles/M = 5.0/0.1 = ? mL