sec=17÷8 and 270°< x <360° (x lies in the fourth quadrant)
I assume you meant secx = 17/8
so the terminal point is at (8,-15)
I don't mind helping to find answers, but I resent having to provide the questions as well.
so the terminal point is at (8,-15)
I don't mind helping to find answers, but I resent having to provide the questions as well.