What is the first 12 term off an ap whose first term is 15 and the common difference is 13
nth term=a+(n-1)d
2nd term= 15+(2-1)13
=28
3rd term= 28+13= 41
4th term=41+13 =54
5th term= 54+13= 67
6th term= 67+13= 80
7th term= 80+13= 93
8th term= 93+13= 106
9th term= 106+13= 119
10th term=119+13= 132
11th term=132+13= 145
12th term=145+13= 158
hence, the first 12 terms are; 15, 28, 41, 54, 67, 80, 93, 106, 119, 132, 145 and 158