The sum of three consecutive numbers is 36 find the three numbers
When the numbers are consecutive, each new number is 1 higher than the previous one.
The numbers are:
x , x + 1 , x + 2
Their sum is:
x + x + 1 + x + 2 = 36
3 x + 3 = 36
Subtract 3 to both sides.
3 x = 33
x = 33 / 3
x = 11
The numbers are:
x , x + 1 , x + 2
11 , 12 , 13