A guitar string has an overall length of 1.28 m and a total mass of 50 g. Once on the guitar, there is distance of 71 cm between its fixed end points. It is tightened to a tension of 810 N.
What is the frequency of the fundamental wave in Hz?
I didn't know, I'm not the same user. Sorry
I told one of my classmates to submit the first problem so we can receive help because we are both struggling with the two problems because you guys have helped me in the past. I didn't know that I would get hate for just asking how to find the speed for the other problem and the frequency for this one.
To find the frequency of the fundamental wave, we can use the equation:
f = (1/2L) * sqrt(T/μ)
where:
f = frequency (in Hz)
L = overall length of the string (in meters)
T = tension in the string (in Newtons)
μ = mass per unit length of the string (in kg/m)
First, let's convert the given values to the appropriate units.
Overall length of the string (L) = 1.28 m
Tension in the string (T) = 810 N
Now we need to calculate the mass per unit length (μ). We can find this by dividing the total mass (m) by the length of the string (L):
μ = m / L
Total mass (m) = 50 g = 0.05 kg
μ = 0.05 kg / 1.28 m ≈ 0.0391 kg/m
Now we can substitute the values into the equation to find the frequency (f):
f = (1/2 * 1.28 m) * sqrt(810 N / 0.0391 kg/m)
Calculating:
f = (0.64) * sqrt(20736.4)
f ≈ 100.53 Hz
Therefore, the frequency of the fundamental wave is approximately 100.53 Hz.
impatient much?
Once is enough, thank you.
Repeated postings will not get faster or better responses.