Calculate the pH of a 4.80M solution of NaOH.
I got 14.68, but is this too high?
I did -log(4.8), then subtracted 14 - (-0.6812) =14.6812
The options are 14.68, 0.681, 4.80, and 13.319.
Thank You
please someone double check my work, I hate to beg, but I need to submit this assignment soon. Thank you so so so much for any consideration.
Your answer is close but not right. Where you did this,
"14 - (-0.6812) =14.6812" you should have done this,
14 - 0.681 = 13.319
You should remember that
pH + pOH = 14 (which is where you get that 14) so you should remember that in water solution the pH can't be greater than 14.