Consider three different liquid E, F and G with the following densities.E=1•51g/cm3, F=1•75g/cm3, G=0•14g/cm3. In which of the liquid would an object of mass 800g and volume 4000cm3.a.sink b.float . Explain your answer
What is the answer
2385846
well, the density of the object is
800g/4000cm^3 = 0.20 g/cm^3
so what do you think?
To determine whether the object would sink or float in each of the liquids E, F, and G, we need to compare the density of the object with the density of each liquid.
Density is calculated by dividing the mass of an object by its volume:
Density = Mass / Volume
Given that the mass of the object is 800g and the volume is 4000cm3, we can calculate its density:
Density of object = 800g / 4000cm3 = 0.2g/cm3
Now let's compare the density of the object with the density of each liquid:
Density of E = 1.51g/cm3
Density of F = 1.75g/cm3
Density of G = 0.14g/cm3
In order for an object to float, its density must be less than the density of the liquid it is placed in. Conversely, if the density of the object is greater than the density of the liquid, the object will sink.
Comparing the density of the object (0.2g/cm3) to the densities of the liquids:
- Density of E (1.51g/cm3): The object's density (0.2g/cm3) is less than the density of E, so the object would float in liquid E.
- Density of F (1.75g/cm3): The object's density (0.2g/cm3) is less than the density of F, so the object would float in liquid F.
- Density of G (0.14g/cm3): The object's density (0.2g/cm3) is greater than the density of G, so the object would sink in liquid G.
Therefore, the object would float in liquids E and F, but sink in liquid G.