P,Q & R ARE 3 VILLAGES SUCH THAT THE BEARING OF Q & R FROM P ARE 325 DEGREES & 055 DEGREES RESPECTIVELY.THE DISTANCE OF Q & R FROM P ARE 5KM & 9KM RESPECTIVELY CALCULATE CORRECT TO NEAREST DEGREE
a)the bearing of Q FROM P
b) the bearing of P from Q
c)DISTANCE OF R FROM Q
PLS ANY RESPONSE
1. Please stop using all-caps. On the internet, that’s interpreted as shouting. It’s not polite.
2. Please have patience. No tutors here are online 24/7.
alright
This one is very similar to the one you posted previously.
I gave you a detailed solution, but you apparently did not understand, even
after I clarified it more.
e.g. in the previous problem one of the bearings was 300°. I claimed that
the remaining angle was 60°, and you did not understand it.
Don't know what else to say.
I understood it but it was not so clear,well i understand it fully now.thank you
do i use the same approach you used for the other question or is there another approach
there's always another approach.
complex numbers, vectors, polar coordinates, geometry, algebra, etc.
thank you but i don't know the approach to use
DRAW IT
Q is 35 deg w of n
R is 35 deg e of n
so angle QPR = 70 deg
setup for law of cosines
QR^2 = 5^2 + 9^2 - 2*5*9 cos 70 = 25 +81 - 30.8 = 75.2
so
QR = 8.67
Use the law of sines for the rest
I think you want the bearing of R not P from Q and you have a typo