The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y plus 7 equals negative StartFraction 2 over 5 EndFraction left-parenthesis x minus 10 right-parenthesis.. What is the standard form of the equation for this line?
2x – 5y = –15
2x – 5y = –17
2x + 5y = –15
2x + 5y = –17
You have
y + 7 = (-2/5)(x-10)
usually done in 3 short steps:
1. multiply both sides by the denominator
5y + 35 = -2(x-10)
2. expand the right side (if needed)
5y + 35 = -2x + 20
3. Bring the x and y terms to one side, leading with a positive x term and
leave the constant on the other side
2x + 5y = -15