Box weight 700N was loaded to truck using an enchained plane of 10m length by applying a force of 500 N the load was lifted a distance of 6m vertically upward based on this answer the question calculate 1. velocity ratio of the machine (3) pts (VR)
2.mechanical advantage of the machine (3)pts (MA)
3.Work output of the machine (3)pts (w°)
Maybe an inclined plane?
Anyway, the pull or push force Times the distance pushed (the length of the ramp) =work done = weight * height in a perfect friction free world
velocity ratio =speed out (length of ramp) / speed in (distance up)
(or sometimes the opposite )10/6 or 6/10
MA = force out / force in = 7/5
work out = weight * height = 700 * 6 = 4200 Joules
work in by the way is 500 * 10 = 5000 Joules
efficiency = 100 * (42/50) = 84%