determine 3 consecutive even integers if the square of the largest integer is 84 less than the sum of the squares of the two smaller integers
let the middle number be x, the previous even be x-2, and the third
consecutive number be x+2
(x^2 + (x-2)^2) - (x+2)^2 = 84
x^2 + x^2 - 4x + 4 - x^2 - 4x - 4 = 84
x^2 - 8x - 84 = 0
(x-14)(x+6) = 0
x = 14 or x = -6
if x = 14, the 3 integers were : 12, 14, and 16
if x = -6, the 3 integers were : -8, -6, -4