Ray runs 30 feet north, 30 feet west, and then 30 feet south. What is the displacement?
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To find the displacement, we need to calculate the net distance and direction from the starting point to the final position.
Since Ray initially runs 30 feet north and then 30 feet south, these two movements cancel each other out in the north-south direction. Therefore, the net displacement in the north-south direction is 0 feet.
Next, Ray runs 30 feet west. This movement would be in the west direction.
So, the displacement would be a vector pointing 30 feet west with a magnitude of 30 feet.
To find the displacement, we need to calculate the straight-line distance and direction from the starting point to the final position. In this case, we can represent the north direction as the positive y-axis and the west direction as the negative x-axis.
From the starting point, if Ray runs 30 feet north, he moves up the positive y-axis by 30 feet. Then, if he runs 30 feet west, he moves left along the negative x-axis, canceling out the 30 feet northward movement. Finally, if he goes 30 feet south, he moves down along the positive y-axis, canceling out the 30 feet westward movement he just made.
Therefore, the 30 feet north and the 30 feet south movements cancel each other out, leaving Ray with a displacement of zero. This means Ray ends up back at the starting point, so the displacement is 0 feet.