A snowball melts in such a way that its diameter is constantly decreasing at a rate of 0.3
cm/min Find the rate of change of the area at the time the radius is 5 cm.
given:
d(diameter)/dt = .3 cm/min
or
d(radius) = ..15 cm/min
Assuming that by area you mean surface area ....
Surface Area = SA
SA = 4π r^2
d(SA)/dt = 8π r dr/dt
d(SA) = 8π(5)(.15)
= 6π cm^2/min