Perimeter of triangle ABC is 24cm . If AC is 4cm longer than BC. Calculate x and y

where does y enter in?

and what about side AB?

To calculate the values of x and y, we need more information about the triangle. Specifically, we need to know the lengths of the sides AB, AC, and BC, or at least one additional piece of information that can help us determine those lengths.

However, since we know the perimeter of the triangle is 24 cm and AC is 4 cm longer than BC, we can set up an equation to help solve for the lengths. Let's define BC as x cm, so AC would be (x + 4) cm.

The perimeter of the triangle is the sum of the lengths of all three sides:

Perimeter = AB + BC + AC

We are given that the perimeter is 24 cm:

24 = AB + x + (x + 4)

Simplifying the equation:

24 = AB + 2x + 4

Rearranging the equation:

AB = 20 - 2x

Now, we know that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. Applying this rule to the triangle, we can set up inequalities for the side lengths:

AB + BC > AC
AB + AC > BC
BC + AC > AB

Substituting the values we have, we get:

(20 - 2x) + x > x + 4
(20 - 2x) + (x + 4) > x
x + (x + 4) > (20 - 2x)

Simplifying the inequalities:

20 - x > 4
20 - x > x
2x + 4 > 20 - 2x

Solving each inequality, we get:

x < 16
x < 10
4x > 16

Therefore, we have a range for x: x < 10.

Since we don't have enough information to calculate the values of x and y precisely, we can only determine that x must be less than 10. The value of y remains unknown without knowing more about the triangle.

To solve for x and y in this scenario, we need more information about the triangle ABC. Could you please provide any additional details or measurements?