What potential difference must be applied across a 1200 Ω resistor in order that
the resulting current be 30 milliamperes?
i R = V
30 *10^-3 * 1.2*10^3= V
V= 1.2*30 = 36 volts
Well, according to Ohm's Law, V = IR. So, we can calculate the potential difference by multiplying the current (30 milliamperes) with the resistance (1200 Ω).
So, the potential difference required would be 36 volts. But hey, if you don't have 36 volts lying around, you can always ask your friendly neighborhood superhero to lend you some extra voltage. Just make sure they're fully charged!
To find the potential difference (voltage) required across a resistor, you can use Ohm's Law, which states that V = I * R, where V is the voltage, I is the current, and R is the resistance.
In this case, the given current is 30 milliamperes, which is equal to 0.03 amperes. The resistance is 1200 Ω.
Using Ohm's Law, we can calculate the potential difference:
V = I * R
V = 0.03 A * 1200 Ω
V = 36 volts
Therefore, a potential difference of 36 volts must be applied across the 1200 Ω resistor in order for the resulting current to be 30 milliamperes.
To find the potential difference (V) required for a given current (I) and resistance (R), you can use Ohm's law, which states that V = I * R.
In this case, you are given the current (I = 30 milliamperes = 30 * 10^(-3) Amperes) and the resistance (R = 1200 Ω). Now, substitute these values into the formula to find the potential difference:
V = I * R
V = (30 * 10^(-3) A) * (1200 Ω)
To do this calculation, convert 30 milliamperes to Amperes:
30 milliamperes = 30 * 10^(-3) Amperes
Now, substitute the values into the formula and calculate the potential difference:
V = (30 * 10^(-3) A) * (1200 Ω)
V = 0.036 V
Therefore, to obtain a current of 30 milliamperes (0.036 A) through a 1200 Ω resistor, a potential difference of 0.036 volts is required.