A shop sells cookies in tins of two different sizes, big and small. The total number of cookies in a bit tin and a small tin is 54. The number of cookies in 2 small tins is 6 more than the number of cookies in a big tin. Find the number of cookies in a big tin.
b+s = 54
2s = b+6
so b = 34
Is that your final answer?
arggghhhh,
since when is 40-6 = 36 ?????
go with dependable oobleck
To find the number of cookies in a big tin, we need to set up equations based on the given information. Let's assume the number of cookies in a big tin is "x" and the number of cookies in a small tin is "y".
From the given information, we know that the total number of cookies in a big tin and a small tin is 54:
x + y = 54 --------------(Equation 1)
We also know that the number of cookies in 2 small tins is 6 more than the number of cookies in a big tin:
2y = x + 6 --------------(Equation 2)
Now, we can solve this system of equations to find the values of x and y. There are different methods to solve this, such as substitution or elimination. In this case, let's use the method of substitution:
From Equation 2, we can rewrite it as x = 2y - 6.
Now, substitute this expression for x in Equation 1:
(2y - 6) + y = 54
3y - 6 = 54
Add 6 to both sides:
3y = 60
Divide by 3:
y = 20
Now substitute the value of y back into Equation 1 to find x:
x + 20 = 54
x = 54 - 20
x = 34
Therefore, the number of cookies in a big tin is 34.
cookies in small tin ---- x
cookies in big tin ----- y
x+y = 54
y = 54-x
also y = 2x - 6
then
2x-6 = 54-x
3x = 60
x = 20
y = 2(20) - 6 = 36
small tin holds 20
big tin holds 36
check: is their sum = 54 ? YES
cookies in 2 small cans = 40
big can holds 36, so 2 small cans hold 6 more than a large can
All is good