(6^3n)^3 = (36^9n)^4 exactly what you have meant, this is the equation need to solve.

(6^3n)^3 = (36^9n)^4

6^(9n) = 36^(36n)
6^(9n) = 6^(72n)
no need to use logs, since the bases are the same,
9n = 72n
only true n = 0
but in your earlier post you said n ≠ 0, so there is no real solution.

Thanks, math helper.....