An automobile with an initial speed of 4.17 m/s accelerates uniformly at the rate of 2.3
m/s2.
Find the final speed of the car after 4.7 s. Answer in units of m.
Find the displacement of the car after 4.7 s. Answer in units of m.
v = v0 + at
s = v0*t + 1/2 at^2
so plug in your values
To find the final speed of the car after 4.7 s, you can use the following formula:
Final Speed (v) = Initial Speed (u) + Acceleration (a) × Time (t)
Given:
Initial Speed (u) = 4.17 m/s
Acceleration (a) = 2.3 m/s^2
Time (t) = 4.7 s
Substituting the given values into the formula:
v = 4.17 m/s + (2.3 m/s^2) × 4.7 s
v = 4.17 m/s + 10.81 m/s
v = 14.98 m/s
Therefore, the final speed of the car after 4.7 s is 14.98 m/s.
To find the displacement of the car after 4.7 s, you can use the following formula:
Displacement (s) = Initial Speed (u) × Time (t) + (1/2) × Acceleration (a) × Time^2 (t^2)
Given:
Initial Speed (u) = 4.17 m/s
Acceleration (a) = 2.3 m/s^2
Time (t) = 4.7 s
Substituting the given values into the formula:
s = (4.17 m/s) × (4.7 s) + (1/2) × (2.3 m/s^2) × (4.7 s)^2
s = 19.569 m + 21.5821 m
s = 41.1511 m
Therefore, the displacement of the car after 4.7 s is 41.1511 m.