Question

What would be the pAg value if 30.00ml of 0.100M AgNO3 was added to a sample containing 30.00ml of 0.100M Br^-? (Ksp= 5.2 ×10^-13 for AgBr)

Answer 1

So you will have a solution of AgBr solid in 60 mL solvent

............AgBr(s) ==> Ag^+ + Br^-
I.............solid..............0.............0
C........solid -x..............x..............x
E..............solid.............x..............x
Ksp = (Ag^+)(Br^-)
5.2E-13 = (x)(x)
Solve for x = (Ag^+) in moles/L, then pAg = -log(Ag^+)