the number of gallons in a fifty gallon fish tank after t number of minutes has passed.
y = -1.5 t + 48
1) Is the tank empty when the time is zero? If not, how many gallons are in the tank?
2) What does the number -1.5 mean in the context of the problem (what is it describing)?
3) After how many minutes would the tank be empty?
1. when t = 0 there are 48 gallons in the tank :)
2, it loses 1.5 gallons per minute
3. 0 = -1.5 t + 48 so t = 48/1.5 when y = 0, a little over half an hour
you have the formula
y= number of gallons = 48 to start - 1.5 * minutes leaking
I would like for someone to please explain the formula that I would use to figure out this problem and others like it. like really explained please.
To find the answers to these questions, we need to use the equation y = -1.5t + 48, where y represents the number of gallons of water in the tank and t represents the number of minutes that have passed.
1) Is the tank empty when the time is zero? If not, how many gallons are in the tank?
To find out if the tank is empty when the time is zero, we substitute t = 0 into the equation:
y = -1.5(0) + 48
y = 0 + 48
y = 48
The tank is not empty when the time is zero. There are 48 gallons of water in the tank.
2) What does the number -1.5 mean in the context of the problem (what is it describing)?
The number -1.5 represents the rate at which the water is being drained from the tank per minute. It is a negative value because the water is decreasing over time.
3) To find out after how many minutes the tank would be empty, we set y = 0 and solve for t:
0 = -1.5t + 48
1.5t = 48
t = 48 / 1.5
t = 32
After 32 minutes, the tank would be empty.