What is the initial value for the equation: y= 24000 (1 - .08)^x ?????
To find the initial value for the equation y = 24000(1 - 0.08)^x, we need to understand what the equation represents. The equation you provided is an exponential decay function, where the variable y represents the final value at a given time x. The initial value refers to the starting value of y when x is equal to zero (x = 0).
In this equation, the value of y is given as 24000. To find the initial value, we can substitute x = 0 into the equation and solve for y.
Plugging in x = 0, the equation becomes:
y = 24000(1 - 0.08)^0
Now, any number raised to the power of zero equals 1. So the equation simplifies to:
y = 24000(1)
Finally, multiplying 24000 by 1 gives us the initial value:
y = 24000
Therefore, the initial value for the given equation y = 24000(1 - 0.08)^x is 24000.
since a^0 = 1 for any a≠0,
y(0) = 24000 * 1 = 24000