What is the initial value for the equation: y = (0.85)^x ??????
0.85^0 = 1
ALL exponentials go through the point (0,1)
In the equation y = (0.85)^x, the initial value refers to the value of y when x is equal to zero.
To find the initial value, substitute x=0 into the equation:
y = (0.85)^0
Any number raised to the power of 0 is equal to 1. Therefore, the initial value for this equation is:
y = 1
To find the initial value for the equation y = (0.85)^x, we need to determine the value of y when x equals zero (x = 0).
Substitute x = 0 into the equation:
y = (0.85)^0
Any number raised to the power of zero is equal to 1. So, the equation simplifies to:
y = 1
Therefore, the initial value for the equation y = (0.85)^x is y = 1.