What is the initial value for the equation y=7500(1+.03)^x
set x=0 and see what you get.
7500
The initial value, or y-intercept, can be determined by evaluating the equation when x = 0.
Let's substitute x = 0 into the equation:
y = 7500(1 + 0.03)^0
Any number raised to the power of 0 is equal to 1, so we have:
y = 7500(1)
Simplifying further:
y = 7500
Therefore, the initial value for the equation y = 7500(1 + 0.03)^x is 7500.
To find the initial value of the equation y = 7500(1 + 0.03)^x, we can use the fact that the initial value occurs when x = 0.
When x = 0, the equation simplifies to:
y = 7500(1 + 0.03)^0
Now, any number raised to the power of 0 is always 1. Therefore, (1 + 0.03)^0 = 1.
Substituting this back into the equation, we get:
y = 7500(1)
Simplifying further, we have:
y = 7500
So, the initial value for the equation y = 7500(1 + 0.03)^x is 7500.