How many moles of KClO3 are needed to produce 50 moles of O2?
The equation tells you the ratio of moles.
The equation is 2KClO3 ----> 2KCl + 3O2
To find the number of moles of KClO3 needed to produce 50 moles of O2, we need to use the balanced chemical equation for the reaction.
The balanced equation for the decomposition of KClO3 is:
2 KClO3 -> 2 KCl + 3 O2
From the equation, we can see that 2 moles of KClO3 produce 3 moles of O2.
So, to find the number of moles of KClO3 needed to produce 50 moles of O2, we can set up a simple proportion:
(2 moles of KClO3) / (3 moles of O2) = (x moles of KClO3) / (50 moles of O2)
Cross-multiplying, we get:
2 * 50 = 3 * x
100 = 3x
Dividing both sides by 3, we find:
x = 100 / 3 ≈ 33.33 moles
Therefore, approximately 33.33 moles of KClO3 are needed to produce 50 moles of O2.